The video. His conclusion is the same as mine. But he’s claiming inrush current was reduced by a 3rd.
I don’t know if inrush current is reduced at all but he only measured 1 (of 2) legs of power with a non RMS meter. There is no way that statement can be made.
Capacitors alter the sine wave so a RMS meter would be required.
Even if current was reduced, watts is actually volts x amps x power factor. Capacitors increase the power factor. So the watts, what you pay for, can be the same while current is lower.
and with the motor starting faster his cheap meter might not have read inrush current as accurately.
