The movie 21 Please explain the math.

[jficquette]

[quote=ucodegen]I agree with you however the games shows want people to win so that people will watch. The merchandise is donated by the manufacturers.

Yes but not easily. It is more important to have people on the edge of their seat than to make winning too easy which would be boring.

I can see where the 66% is coming from, the problem is the information being added to the system in the middle and between sets for selections. After the added information, are they independent runs?[/quote]

I consider them independent runs so I say 50/50. Your’re right too they want to make it look hard but showing one of the doors that does not have the prize effectively makes it 50/50 so they know that over time there will be enough winna’s to keep people tuned in etc.

John

[ucodegen]

I consider them independent runs so I say 50/50. Your’re right too they want to make it look hard but showing one of the doors effectively makes it 50/50 so they know that over time there will be enough winna’s to keep people tuned it etc.

I’m not convinced on their independence. I am coming up with 33% on a car and 66% chance on a goat going into the reveal. While the next choice is binary when independent, the entrance condition alters the probability.

[ucodegen]

I consider them independent runs so I say 50/50. Your’re right too they want to make it look hard but showing one of the doors effectively makes it 50/50 so they know that over time there will be enough winna’s to keep people tuned it etc.

I’m not convinced on their independence. I am coming up with 33% on a car and 66% chance on a goat going into the reveal. While the next choice is binary when independent, the entrance condition alters the probability.

[ucodegen]

I consider them independent runs so I say 50/50. Your’re right too they want to make it look hard but showing one of the doors effectively makes it 50/50 so they know that over time there will be enough winna’s to keep people tuned it etc.

I’m not convinced on their independence. I am coming up with 33% on a car and 66% chance on a goat going into the reveal. While the next choice is binary when independent, the entrance condition alters the probability.

[ucodegen]

I consider them independent runs so I say 50/50. Your’re right too they want to make it look hard but showing one of the doors effectively makes it 50/50 so they know that over time there will be enough winna’s to keep people tuned it etc.

I’m not convinced on their independence. I am coming up with 33% on a car and 66% chance on a goat going into the reveal. While the next choice is binary when independent, the entrance condition alters the probability.

[ucodegen]

I consider them independent runs so I say 50/50. Your’re right too they want to make it look hard but showing one of the doors effectively makes it 50/50 so they know that over time there will be enough winna’s to keep people tuned it etc.

I’m not convinced on their independence. I am coming up with 33% on a car and 66% chance on a goat going into the reveal. While the next choice is binary when independent, the entrance condition alters the probability.

[citydweller]

I have to agree with Brian P. If there are 10 doors your chance of picking the car is only 10%. The host opens 8 doors that have goats. Your best bet is to switch doors, since the probability of having picked the car on your first choice is still only 10%.

I’m assuming the host knows which door has the car behind it.

[citydweller]

I have to agree with Brian P. If there are 10 doors your chance of picking the car is only 10%. The host opens 8 doors that have goats. Your best bet is to switch doors, since the probability of having picked the car on your first choice is still only 10%.

I’m assuming the host knows which door has the car behind it.

[citydweller]

I have to agree with Brian P. If there are 10 doors your chance of picking the car is only 10%. The host opens 8 doors that have goats. Your best bet is to switch doors, since the probability of having picked the car on your first choice is still only 10%.

I’m assuming the host knows which door has the car behind it.

[citydweller]

I have to agree with Brian P. If there are 10 doors your chance of picking the car is only 10%. The host opens 8 doors that have goats. Your best bet is to switch doors, since the probability of having picked the car on your first choice is still only 10%.

I’m assuming the host knows which door has the car behind it.

[citydweller]

I have to agree with Brian P. If there are 10 doors your chance of picking the car is only 10%. The host opens 8 doors that have goats. Your best bet is to switch doors, since the probability of having picked the car on your first choice is still only 10%.

I’m assuming the host knows which door has the car behind it.

[meadandale]

I don’t know why some of you people are arguing against the 2/3 answer. It IS the correct answer, whether you understand the logic or not.

People who study probabilities for a living have said this is the answer. All you amateur naysayers should just capitulate and move on…:-)

[meadandale]

I don’t know why some of you people are arguing against the 2/3 answer. It IS the correct answer, whether you understand the logic or not.

People who study probabilities for a living have said this is the answer. All you amateur naysayers should just capitulate and move on…:-)

[meadandale]

I don’t know why some of you people are arguing against the 2/3 answer. It IS the correct answer, whether you understand the logic or not.

People who study probabilities for a living have said this is the answer. All you amateur naysayers should just capitulate and move on…:-)

[meadandale]

I don’t know why some of you people are arguing against the 2/3 answer. It IS the correct answer, whether you understand the logic or not.

People who study probabilities for a living have said this is the answer. All you amateur naysayers should just capitulate and move on…:-)

[Author]

Posts